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Integrations and complex functions

Integrations and complex functions Integrations and complex functions ,Let ๐‘“(๐‘ฅ) = โˆš๐‘ฅ โˆ’ 3 and ๐‘”(๐‘ฅ) = (๐‘ฅ โˆ’ 3)2, find (๐‘”๐‘œ๐‘“)(7). solutions Answer: gof (7) = 1 f (7) = โˆšx-3 =โˆš4 =2. Work: (gof)(7)= g(f(7))= f(7)= g(2) g(2)= (x-3)2 = (2-3)2 =(-1)2 =1. Integrations and complex functions, Let ๐‘“(๐‘ฅ) = โˆš๐‘ฅ โˆ’ 3 […]

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Mathematics: Laws of Logarithms

Mathematics: Laws of Logarithms, Evaluate the expression: ๐‘™๐‘œ๐‘”1/5(1) Mathematics: Logarithms and calculus , Evaluate the expression: ๐‘™๐‘œ๐‘”1/5(1)   solution     Answer: log1/5 (1) = 0.   Work: Law of logs says, the Log of 1 to any base is 0. LINK N.B law of logarithmshttps://libguides.csudh.edu/citation/apa-7   Evaluate the expression: ๐‘™๐‘œ๐‘”1/5(1) Mathematics: Logarithms and calculus

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Basic math: Expressions, Indices and Logarithms

Basic math: Mathematics, Expressions, Indices and Logarithms Evaluate the expression: ๐‘™๐‘œ๐‘”82 solution   Answers: x =1/3   Work: rewrite the log to express the unknown value of x Log82 =x Remove the log, 8x=2 the we solve this by reducing 8 to base 2. Therefore, 8x=2 becomes 2(3)x =21 . the bases are the same

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Algorithms and Domain functions

  Domain functions and Algorithms : Find the domain of the function: ๐‘“(๐‘ฅ) = ๐‘™๐‘œ๐‘”4 (4 โˆ’ 3๐‘ฅ).   solutions Answer: x= 4/3, so the domain is (4/3, โˆž)   Work: We identify the argument which 4-3x, argument >0 4-3x>0, solving for x, then -3x>-4 rewrite the domain function, 3x>4 x>4/3 Our domain is {x|x>4/3}

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